x^2+21x-1080=0

Solution for x^2+21x-1080=0 equation:

x^2+21x-1080=0

a = 1; b = 21; c = -1080;
Δ = b2-4ac
Δ = 212-4·1·(-1080)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-69}{2*1}=\frac{-90}{2}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+69}{2*1}=\frac{48}{2}
=24
$